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			66 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			Go
		
	
	
	
		
			Vendored
		
	
	
	
			
		
		
	
	
			66 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			Go
		
	
	
	
		
			Vendored
		
	
	
	
| // SPDX-License-Identifier: MIT
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| 
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| package identicon
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| 
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| var (
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| 	// 4 个元素分别表示 cos(0),cos(90),cos(180),cos(270)
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| 	cos = []int{1, 0, -1, 0}
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| 
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| 	// 4 个元素分别表示 sin(0),sin(90),sin(180),sin(270)
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| 	sin = []int{0, 1, 0, -1}
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| )
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| 
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| // 将 points 中的所有点,以 x,y 为原点旋转 angle 个角度。
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| // angle 取值只能是 [0,1,2,3],分别表示 [0,90,180,270]
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| func rotate(points []int, x, y int, angle int) {
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| 	if angle < 0 || angle > 3 {
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| 		panic("rotate:参数angle必须0,1,2,3三值之一")
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| 	}
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| 
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| 	for i := 0; i < len(points); i += 2 {
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| 		px, py := points[i]-x, points[i+1]-y
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| 		points[i] = px*cos[angle] - py*sin[angle] + x
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| 		points[i+1] = px*sin[angle] + py*cos[angle] + y
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| 	}
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| }
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| 
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| // 判断某个点是否在多边形之内,不包含构成多边形的线和点
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| // x,y 需要判断的点坐标
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| // points 组成多边形的所顶点,每两个元素表示一点顶点,其中最后一个顶点必须与第一个顶点相同。
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| func pointInPolygon(x, y int, points []int) bool {
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| 	if len(points) < 8 { // 只有2个以上的点,才能组成闭合多边形
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| 		return false
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| 	}
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| 
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| 	// 大致算法如下:
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| 	// 把整个平面以给定的测试点为原点分两部分:
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| 	// - y>0,包含(x>0 && y==0)
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| 	// - y<0,包含(x<0 && y==0)
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| 	// 依次扫描每一个点,当该点与前一个点处于不同部分时(即一个在 y>0 区,一个在 y<0 区),
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| 	// 则判断从前一点到当前点是顺时针还是逆时针(以给定的测试点为原点),如果是顺时针 r++,否则 r--。
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| 	// 结果为:2==abs(r)。
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| 
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| 	r := 0
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| 	x1, y1 := points[0], points[1]
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| 	prev := (y1 > y) || ((x1 > x) && (y1 == y))
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| 	for i := 2; i < len(points); i += 2 {
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| 		x2, y2 := points[i], points[i+1]
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| 		curr := (y2 > y) || ((x2 > x) && (y2 == y))
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| 
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| 		if curr == prev {
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| 			x1, y1 = x2, y2
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| 			continue
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| 		}
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| 
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| 		if mul := (x1-x)*(y2-y) - (x2-x)*(y1-y); mul >= 0 {
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| 			r++
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| 		} else if mul < 0 {
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| 			r--
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| 		}
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| 		x1, y1 = x2, y2
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| 		prev = curr
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| 	}
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| 
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| 	return r == 2 || r == -2
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| }
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